3.24.96 \(\int \frac {(1-2 x)^{5/2} \sqrt {3+5 x}}{(2+3 x)^5} \, dx\) [2396]

Optimal. Leaf size=151 \[ -\frac {6655 \sqrt {1-2 x} \sqrt {3+5 x}}{448 (2+3 x)}+\frac {(1-2 x)^{5/2} (3+5 x)^{3/2}}{4 (2+3 x)^4}+\frac {55 (1-2 x)^{3/2} (3+5 x)^{3/2}}{24 (2+3 x)^3}+\frac {605 \sqrt {1-2 x} (3+5 x)^{3/2}}{32 (2+3 x)^2}-\frac {73205 \tan ^{-1}\left (\frac {\sqrt {1-2 x}}{\sqrt {7} \sqrt {3+5 x}}\right )}{448 \sqrt {7}} \]

[Out]

1/4*(1-2*x)^(5/2)*(3+5*x)^(3/2)/(2+3*x)^4+55/24*(1-2*x)^(3/2)*(3+5*x)^(3/2)/(2+3*x)^3-73205/3136*arctan(1/7*(1
-2*x)^(1/2)*7^(1/2)/(3+5*x)^(1/2))*7^(1/2)+605/32*(3+5*x)^(3/2)*(1-2*x)^(1/2)/(2+3*x)^2-6655/448*(1-2*x)^(1/2)
*(3+5*x)^(1/2)/(2+3*x)

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Rubi [A]
time = 0.03, antiderivative size = 151, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 3, integrand size = 26, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.115, Rules used = {96, 95, 210} \begin {gather*} -\frac {73205 \text {ArcTan}\left (\frac {\sqrt {1-2 x}}{\sqrt {7} \sqrt {5 x+3}}\right )}{448 \sqrt {7}}+\frac {(5 x+3)^{3/2} (1-2 x)^{5/2}}{4 (3 x+2)^4}+\frac {55 (5 x+3)^{3/2} (1-2 x)^{3/2}}{24 (3 x+2)^3}+\frac {605 (5 x+3)^{3/2} \sqrt {1-2 x}}{32 (3 x+2)^2}-\frac {6655 \sqrt {5 x+3} \sqrt {1-2 x}}{448 (3 x+2)} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[((1 - 2*x)^(5/2)*Sqrt[3 + 5*x])/(2 + 3*x)^5,x]

[Out]

(-6655*Sqrt[1 - 2*x]*Sqrt[3 + 5*x])/(448*(2 + 3*x)) + ((1 - 2*x)^(5/2)*(3 + 5*x)^(3/2))/(4*(2 + 3*x)^4) + (55*
(1 - 2*x)^(3/2)*(3 + 5*x)^(3/2))/(24*(2 + 3*x)^3) + (605*Sqrt[1 - 2*x]*(3 + 5*x)^(3/2))/(32*(2 + 3*x)^2) - (73
205*ArcTan[Sqrt[1 - 2*x]/(Sqrt[7]*Sqrt[3 + 5*x])])/(448*Sqrt[7])

Rule 95

Int[(((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_))/((e_.) + (f_.)*(x_)), x_Symbol] :> With[{q = Denomin
ator[m]}, Dist[q, Subst[Int[x^(q*(m + 1) - 1)/(b*e - a*f - (d*e - c*f)*x^q), x], x, (a + b*x)^(1/q)/(c + d*x)^
(1/q)], x]] /; FreeQ[{a, b, c, d, e, f}, x] && EqQ[m + n + 1, 0] && RationalQ[n] && LtQ[-1, m, 0] && SimplerQ[
a + b*x, c + d*x]

Rule 96

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p_.), x_Symbol] :> Simp[(a + b*
x)^(m + 1)*(c + d*x)^n*((e + f*x)^(p + 1)/((m + 1)*(b*e - a*f))), x] - Dist[n*((d*e - c*f)/((m + 1)*(b*e - a*f
))), Int[(a + b*x)^(m + 1)*(c + d*x)^(n - 1)*(e + f*x)^p, x], x] /; FreeQ[{a, b, c, d, e, f, m, p}, x] && EqQ[
m + n + p + 2, 0] && GtQ[n, 0] && (SumSimplerQ[m, 1] ||  !SumSimplerQ[p, 1]) && NeQ[m, -1]

Rule 210

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(-(Rt[-a, 2]*Rt[-b, 2])^(-1))*ArcTan[Rt[-b, 2]*(x/Rt[-a, 2])
], x] /; FreeQ[{a, b}, x] && PosQ[a/b] && (LtQ[a, 0] || LtQ[b, 0])

Rubi steps

\begin {align*} \int \frac {(1-2 x)^{5/2} \sqrt {3+5 x}}{(2+3 x)^5} \, dx &=\frac {(1-2 x)^{5/2} (3+5 x)^{3/2}}{4 (2+3 x)^4}+\frac {55}{8} \int \frac {(1-2 x)^{3/2} \sqrt {3+5 x}}{(2+3 x)^4} \, dx\\ &=\frac {(1-2 x)^{5/2} (3+5 x)^{3/2}}{4 (2+3 x)^4}+\frac {55 (1-2 x)^{3/2} (3+5 x)^{3/2}}{24 (2+3 x)^3}+\frac {605}{16} \int \frac {\sqrt {1-2 x} \sqrt {3+5 x}}{(2+3 x)^3} \, dx\\ &=\frac {(1-2 x)^{5/2} (3+5 x)^{3/2}}{4 (2+3 x)^4}+\frac {55 (1-2 x)^{3/2} (3+5 x)^{3/2}}{24 (2+3 x)^3}+\frac {605 \sqrt {1-2 x} (3+5 x)^{3/2}}{32 (2+3 x)^2}+\frac {6655}{64} \int \frac {\sqrt {3+5 x}}{\sqrt {1-2 x} (2+3 x)^2} \, dx\\ &=-\frac {6655 \sqrt {1-2 x} \sqrt {3+5 x}}{448 (2+3 x)}+\frac {(1-2 x)^{5/2} (3+5 x)^{3/2}}{4 (2+3 x)^4}+\frac {55 (1-2 x)^{3/2} (3+5 x)^{3/2}}{24 (2+3 x)^3}+\frac {605 \sqrt {1-2 x} (3+5 x)^{3/2}}{32 (2+3 x)^2}+\frac {73205}{896} \int \frac {1}{\sqrt {1-2 x} (2+3 x) \sqrt {3+5 x}} \, dx\\ &=-\frac {6655 \sqrt {1-2 x} \sqrt {3+5 x}}{448 (2+3 x)}+\frac {(1-2 x)^{5/2} (3+5 x)^{3/2}}{4 (2+3 x)^4}+\frac {55 (1-2 x)^{3/2} (3+5 x)^{3/2}}{24 (2+3 x)^3}+\frac {605 \sqrt {1-2 x} (3+5 x)^{3/2}}{32 (2+3 x)^2}+\frac {73205}{448} \text {Subst}\left (\int \frac {1}{-7-x^2} \, dx,x,\frac {\sqrt {1-2 x}}{\sqrt {3+5 x}}\right )\\ &=-\frac {6655 \sqrt {1-2 x} \sqrt {3+5 x}}{448 (2+3 x)}+\frac {(1-2 x)^{5/2} (3+5 x)^{3/2}}{4 (2+3 x)^4}+\frac {55 (1-2 x)^{3/2} (3+5 x)^{3/2}}{24 (2+3 x)^3}+\frac {605 \sqrt {1-2 x} (3+5 x)^{3/2}}{32 (2+3 x)^2}-\frac {73205 \tan ^{-1}\left (\frac {\sqrt {1-2 x}}{\sqrt {7} \sqrt {3+5 x}}\right )}{448 \sqrt {7}}\\ \end {align*}

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Mathematica [A]
time = 0.27, size = 79, normalized size = 0.52 \begin {gather*} \frac {\frac {7 \sqrt {1-2 x} \sqrt {3+5 x} \left (164688+723428 x+1059032 x^2+518715 x^3\right )}{(2+3 x)^4}-219615 \sqrt {7} \tan ^{-1}\left (\frac {\sqrt {1-2 x}}{\sqrt {7} \sqrt {3+5 x}}\right )}{9408} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[((1 - 2*x)^(5/2)*Sqrt[3 + 5*x])/(2 + 3*x)^5,x]

[Out]

((7*Sqrt[1 - 2*x]*Sqrt[3 + 5*x]*(164688 + 723428*x + 1059032*x^2 + 518715*x^3))/(2 + 3*x)^4 - 219615*Sqrt[7]*A
rcTan[Sqrt[1 - 2*x]/(Sqrt[7]*Sqrt[3 + 5*x])])/9408

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Maple [B] Leaf count of result is larger than twice the leaf count of optimal. \(249\) vs. \(2(118)=236\).
time = 0.11, size = 250, normalized size = 1.66

method	result	size
risch	\(-\frac {\sqrt {3+5 x}\, \left (-1+2 x \right ) \left (518715 x^{3}+1059032 x^{2}+723428 x +164688\right ) \sqrt {\left (1-2 x \right ) \left (3+5 x \right )}}{1344 \left (2+3 x \right )^{4} \sqrt {-\left (3+5 x \right ) \left (-1+2 x \right )}\, \sqrt {1-2 x}}+\frac {73205 \sqrt {7}\, \arctan \left (\frac {9 \left (\frac {20}{3}+\frac {37 x}{3}\right ) \sqrt {7}}{14 \sqrt {-90 \left (\frac {2}{3}+x \right )^{2}+67+111 x}}\right ) \sqrt {\left (1-2 x \right ) \left (3+5 x \right )}}{6272 \sqrt {1-2 x}\, \sqrt {3+5 x}}\)	\(129\)
default	\(\frac {\sqrt {1-2 x}\, \sqrt {3+5 x}\, \left (17788815 \sqrt {7}\, \arctan \left (\frac {\left (37 x +20\right ) \sqrt {7}}{14 \sqrt {-10 x^{2}-x +3}}\right ) x^{4}[phone] \sqrt {7}\, \arctan \left (\frac {\left (37 x +20\right ) \sqrt {7}}{14 \sqrt {-10 x^{2}-x +3}}\right ) x^{3}[phone] \sqrt {7}\, \arctan \left (\frac {\left (37 x +20\right ) \sqrt {7}}{14 \sqrt {-10 x^{2}-x +3}}\right ) x^{2}+7262010 x^{3} \sqrt {-10 x^{2}-x +3}[phone] \sqrt {7}\, \arctan \left (\frac {\left (37 x +20\right ) \sqrt {7}}{14 \sqrt {-10 x^{2}-x +3}}\right ) x [phone] x^{2} \sqrt {-10 x^{2}-x +3}+3513840 \sqrt {7}\, \arctan \left (\frac {\left (37 x +20\right ) \sqrt {7}}{14 \sqrt {-10 x^{2}-x +3}}\right )[phone] x \sqrt {-10 x^{2}-x +3}+2305632 \sqrt {-10 x^{2}-x +3}\right )}{18816 \sqrt {-10 x^{2}-x +3}\, \left (2+3 x \right )^{4}}\)	\(250\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((1-2*x)^(5/2)*(3+5*x)^(1/2)/(2+3*x)^5,x,method=_RETURNVERBOSE)

[Out]

1/18816*(1-2*x)^(1/2)*(3+5*x)^(1/2)*(17788815*7^(1/2)*arctan(1/14*(37*x+20)*7^(1/2)/(-10*x^2-x+3)^(1/2))*x^4+4
7436840*7^(1/2)*arctan(1/14*(37*x+20)*7^(1/2)/(-10*x^2-x+3)^(1/2))*x^3+47436840*7^(1/2)*arctan(1/14*(37*x+20)*
7^(1/2)/(-10*x^2-x+3)^(1/2))*x^2+7262010*x^3*(-10*x^2-x+3)^(1/2)[phone]*7^(1/2)*arctan(1/14*(37*x+20)*7^(1/2
)/(-10*x^2-x+3)^(1/2))*x+14826448*x^2*(-10*x^2-x+3)^(1/2)+3513840*7^(1/2)*arctan(1/14*(37*x+20)*7^(1/2)/(-10*x
^2-x+3)^(1/2))[phone]*x*(-10*x^2-x+3)^(1/2)+2305632*(-10*x^2-x+3)^(1/2))/(-10*x^2-x+3)^(1/2)/(2+3*x)^4

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Maxima [A]
time = 0.49, size = 157, normalized size = 1.04 \begin {gather*} \frac {73205}{6272} \, \sqrt {7} \arcsin \left (\frac {37 \, x}{11 \, {\left | 3 \, x + 2 \right |}} + \frac {20}{11 \, {\left | 3 \, x + 2 \right |}}\right ) + \frac {3025}{336} \, \sqrt {-10 \, x^{2} - x + 3} + \frac {7 \, {\left (-10 \, x^{2} - x + 3\right )}^{\frac {3}{2}}}{12 \, {\left (81 \, x^{4} + 216 \, x^{3} + 216 \, x^{2} + 96 \, x + 16\right )}} + \frac {17 \, {\left (-10 \, x^{2} - x + 3\right )}^{\frac {3}{2}}}{8 \, {\left (27 \, x^{3} + 54 \, x^{2} + 36 \, x + 8\right )}} + \frac {1815 \, {\left (-10 \, x^{2} - x + 3\right )}^{\frac {3}{2}}}{224 \, {\left (9 \, x^{2} + 12 \, x + 4\right )}} - \frac {22385 \, \sqrt {-10 \, x^{2} - x + 3}}{1344 \, {\left (3 \, x + 2\right )}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1-2*x)^(5/2)*(3+5*x)^(1/2)/(2+3*x)^5,x, algorithm="maxima")

[Out]

73205/6272*sqrt(7)*arcsin(37/11*x/abs(3*x + 2) + 20/11/abs(3*x + 2)) + 3025/336*sqrt(-10*x^2 - x + 3) + 7/12*(
-10*x^2 - x + 3)^(3/2)/(81*x^4 + 216*x^3 + 216*x^2 + 96*x + 16) + 17/8*(-10*x^2 - x + 3)^(3/2)/(27*x^3 + 54*x^
2 + 36*x + 8) + 1815/224*(-10*x^2 - x + 3)^(3/2)/(9*x^2 + 12*x + 4) - 22385/1344*sqrt(-10*x^2 - x + 3)/(3*x +
2)

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Fricas [A]
time = 0.52, size = 116, normalized size = 0.77 \begin {gather*} -\frac {219615 \, \sqrt {7} {\left (81 \, x^{4} + 216 \, x^{3} + 216 \, x^{2} + 96 \, x + 16\right )} \arctan \left (\frac {\sqrt {7} {\left (37 \, x + 20\right )} \sqrt {5 \, x + 3} \sqrt {-2 \, x + 1}}{14 \, {\left (10 \, x^{2} + x - 3\right )}}\right ) - 14 \, {\left (518715 \, x^{3} + 1059032 \, x^{2} + 723428 \, x + 164688\right )} \sqrt {5 \, x + 3} \sqrt {-2 \, x + 1}}{18816 \, {\left (81 \, x^{4} + 216 \, x^{3} + 216 \, x^{2} + 96 \, x + 16\right )}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1-2*x)^(5/2)*(3+5*x)^(1/2)/(2+3*x)^5,x, algorithm="fricas")

[Out]

-1/18816*(219615*sqrt(7)*(81*x^4 + 216*x^3 + 216*x^2 + 96*x + 16)*arctan(1/14*sqrt(7)*(37*x + 20)*sqrt(5*x + 3
)*sqrt(-2*x + 1)/(10*x^2 + x - 3)) - 14*(518715*x^3 + 1059032*x^2 + 723428*x + 164688)*sqrt(5*x + 3)*sqrt(-2*x
+ 1))/(81*x^4 + 216*x^3 + 216*x^2 + 96*x + 16)

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Sympy [F(-1)] Timed out
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1-2*x)**(5/2)*(3+5*x)**(1/2)/(2+3*x)**5,x)

[Out]

Timed out

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Giac [B] Leaf count of result is larger than twice the leaf count of optimal. 368 vs. \(2 (118) = 236\).
time = 0.82, size = 368, normalized size = 2.44 \begin {gather*} \frac {14641}{12544} \, \sqrt {70} \sqrt {10} {\left (\pi + 2 \, \arctan \left (-\frac {\sqrt {70} \sqrt {5 \, x + 3} {\left (\frac {{\left (\sqrt {2} \sqrt {-10 \, x + 5} - \sqrt {22}\right )}^{2}}{5 \, x + 3} - 4\right )}}{140 \, {\left (\sqrt {2} \sqrt {-10 \, x + 5} - \sqrt {22}\right )}}\right )\right )} - \frac {73205 \, \sqrt {10} {\left (3 \, {\left (\frac {\sqrt {2} \sqrt {-10 \, x + 5} - \sqrt {22}}{\sqrt {5 \, x + 3}} - \frac {4 \, \sqrt {5 \, x + 3}}{\sqrt {2} \sqrt {-10 \, x + 5} - \sqrt {22}}\right )}^{7} - 4088 \, {\left (\frac {\sqrt {2} \sqrt {-10 \, x + 5} - \sqrt {22}}{\sqrt {5 \, x + 3}} - \frac {4 \, \sqrt {5 \, x + 3}}{\sqrt {2} \sqrt {-10 \, x + 5} - \sqrt {22}}\right )}^{5} - 862400 \, {\left (\frac {\sqrt {2} \sqrt {-10 \, x + 5} - \sqrt {22}}{\sqrt {5 \, x + 3}} - \frac {4 \, \sqrt {5 \, x + 3}}{\sqrt {2} \sqrt {-10 \, x + 5} - \sqrt {22}}\right )}^{3} - \frac {65856000 \, {\left (\sqrt {2} \sqrt {-10 \, x + 5} - \sqrt {22}\right )}}{\sqrt {5 \, x + 3}} + \frac {263424000 \, \sqrt {5 \, x + 3}}{\sqrt {2} \sqrt {-10 \, x + 5} - \sqrt {22}}\right )}}{672 \, {\left ({\left (\frac {\sqrt {2} \sqrt {-10 \, x + 5} - \sqrt {22}}{\sqrt {5 \, x + 3}} - \frac {4 \, \sqrt {5 \, x + 3}}{\sqrt {2} \sqrt {-10 \, x + 5} - \sqrt {22}}\right )}^{2} + 280\right )}^{4}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1-2*x)^(5/2)*(3+5*x)^(1/2)/(2+3*x)^5,x, algorithm="giac")

[Out]

14641/12544*sqrt(70)*sqrt(10)*(pi + 2*arctan(-1/140*sqrt(70)*sqrt(5*x + 3)*((sqrt(2)*sqrt(-10*x + 5) - sqrt(22
))^2/(5*x + 3) - 4)/(sqrt(2)*sqrt(-10*x + 5) - sqrt(22)))) - 73205/672*sqrt(10)*(3*((sqrt(2)*sqrt(-10*x + 5) -
sqrt(22))/sqrt(5*x + 3) - 4*sqrt(5*x + 3)/(sqrt(2)*sqrt(-10*x + 5) - sqrt(22)))^7 - 4088*((sqrt(2)*sqrt(-10*x
+ 5) - sqrt(22))/sqrt(5*x + 3) - 4*sqrt(5*x + 3)/(sqrt(2)*sqrt(-10*x + 5) - sqrt(22)))^5 - 862400*((sqrt(2)*s
qrt(-10*x + 5) - sqrt(22))/sqrt(5*x + 3) - 4*sqrt(5*x + 3)/(sqrt(2)*sqrt(-10*x + 5) - sqrt(22)))^3 - 65856000*
(sqrt(2)*sqrt(-10*x + 5) - sqrt(22))/sqrt(5*x + 3) + 263424000*sqrt(5*x + 3)/(sqrt(2)*sqrt(-10*x + 5) - sqrt(2
2)))/(((sqrt(2)*sqrt(-10*x + 5) - sqrt(22))/sqrt(5*x + 3) - 4*sqrt(5*x + 3)/(sqrt(2)*sqrt(-10*x + 5) - sqrt(22
)))^2 + 280)^4

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Mupad [F]
time = 0.00, size = -1, normalized size = -0.01 \begin {gather*} \int \frac {{\left (1-2\,x\right )}^{5/2}\,\sqrt {5\,x+3}}{{\left (3\,x+2\right )}^5} \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(((1 - 2*x)^(5/2)*(5*x + 3)^(1/2))/(3*x + 2)^5,x)

[Out]

int(((1 - 2*x)^(5/2)*(5*x + 3)^(1/2))/(3*x + 2)^5, x)

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